Finding Integral Part of Numbers of the Form a^b Where a Is Irrational
Trending Questions
Q. If the constant term, in binomial expansion (2xr+1x2)10 is 180, then r is equal to
Q. If S=75+952+1353+1954+⋯, then 160S is equal to
Q. The last two digits of the number 3400 is
- 43
- 29
- 81
- 01
Q. If {x} represents the fractional part of x, then {52008} is
- 38
- 58
- 14
- 18
Q. Consider the binomial expansion R=(1+2x)n=I+f, where I is the integral part of R and f is the fractional part of R for n∈N. If the sum of the coefficients of R is 6561 and K=n+R−Rf, then which of the following is/are correct?
- K=9 when x=1√2
- K=7 when x=1√2
- 5th term is the greatest term when x=12
- If kth term has the greatest coefficient, then the sum of all possible value(s) of k is 13
Q. If p=(8+3√7)n and f=p−[p], then the value of p(1−f) is
(where [.] denotes the greatest integer function)
(where [.] denotes the greatest integer function)
- 1
- 2
- 2n
- 22n
Q. If 97+79 is divided by 64, then the remainder is
- 1
- 11
- 0
- 61
Q.
Find the square root of in radical form
Q.
If m is a positive integer, then [(√3+1)2m]+1, where [x] denotes greatest integer ≤x, is divisible by
- 2m
- 2m+1
- 2m+1−2
- 22m
Q. If f(x)=x−x2+x3−x4⋯∞ and |x|<1, then f′(x)=
- 1(1+x)
- 1(1+x)2
- 1(1−x)
- 1(1−x)2
Q. Let A is a non-singular matrix such that A2=I. Then the inverse of A2 will be (where I= identity matrix)
- 2A
- A−12
- A2
- A2
Q. Statement 1:
If p is a prime number (p≠2), then [(2+√5)p]−2p+1 is always divisible by p (where [.] denotes the greatest integer function).
Statement 2:
If n is a prime, then nC1, nC2, nC3, …, nCn−1 must be divisible by n.
If p is a prime number (p≠2), then [(2+√5)p]−2p+1 is always divisible by p (where [.] denotes the greatest integer function).
Statement 2:
If n is a prime, then nC1, nC2, nC3, …, nCn−1 must be divisible by n.
- Both the statements are TRUE and STATEMENT 2 is the correct explanation of STATEMENT 1.
- Both the statements are TRUE and STATEMENT 2 is NOT the correct explanation of STATEMENT 1.
- STATEMENT 1 is TRUE and STATEMENT 2 is FALSE.
- STATEMENT 1 is FALSE and STATEMENT 2 is TRUE.
Q. If 15C3r=15Cr+3, then the value of r is ........
3
4
5
8
Q. The value of 11!(n−1)!+13!(n−3)!+…+1(n−1)!(1)!, where n is even positive integer, is
- 2n(n−1)!
- 2n−1n!
- 2n+1n!
- 2n(n+1)!
Q. The value of {24n15}, n∈N is
(where {.} represents fractional part function)
(where {.} represents fractional part function)
- 115
- 1115
- 415
- 1415
Q. If n is positive integer and (3√3+5)2n+1=α+β where α is an integer and 0<β<1, then
Q.
Find the greater number in 300! and √300300
Can't be determined.
300!
√300300
300! = √300300
Q. In Im, n=∫10xm−1(1−x)n−1dx, for m, n≥1 and ∫10xm−1+xn−1(1+x)m+ndx=αIm, n, α∈R, then α equals
Q.
Which of the following is true about (√3+1)2n, where n is a positive integer
The integer just above it is an even number
The integer above it is divisible by
The integer just above it is divisible by 3
The integer just above is divisible by
Q. If (5−√21)2n+1 and f = R –[[R], where [R]denotes the greatest integer less than or equal to R, then R(1−f) =
Q. If ∫x2−x+1(x2+1)32exdx=exf(x)+c, then which of the following is/are true:
- f(x) is an even function
- f(x) is an odd function
- The range of f(x) is (0, 1]
- f(1)=12
Q.
What is the value of ?
Q. If n be a positive integer and (7+4√3)n=p+β, where p is a positive integer and β is a proper fraction, then
- (1−β)(p+β)=2
- (1−β)1/n+(p+β)1/n=14
- (1−β)(p+β)=1
- (1−β)1/n+(p+β)1/n=8√3
Q. If f is an even function defined on the interval [−5, 5], then the real values of x satisfying the equation f(x)=f(x+1x+2) are
- −1±√52
- −2±√52
- non of these
- −3±√52
Q. ∫x2ex(x+2)2dx is equal to
- ex[x−2x+2]+C
- ex[4(x+2)2]+C
- ex[1x+2]+C
- ex[x2(x+2)2]+C
Q.
The greatest integer less than or equal to (√2+1)6 is
196
197
198
199
Q. ∫(x+2x+4)2exdx is equal to
- ex(xx+4)+C
- ex(x+2x+4)+C
- ex(x−2x+4)+C
- (2xe2x+4)+C
Q. If 683+883 is divided by 49, then the remainder is
- 35
- 5
- 1
- 0
Q. A 7-digit number is formed using the digits from 1, 2, 3, ⋯, 9 such that exactly one digit is repeated thrice and exactly one digit is repeated twice. The total number of such 7-digit number is
- 9C1× 8C1× 7C5×7!3!×2!
- 9×9×9×8×8×7×6
- 9C2× 7C5×7!5!
- 7!3!×2!
Q.
Find (5√5+11)2n+1 - (5√5−11)2n+1
2[ - ..............]
2[ + ..............]
2[ + ..............]
2[ - ..............]